In a hydrogen atom, if energy of an electron in ground state is - 13.6 eV , then energy in the 2^nd excited state is A. - 1.51 eV B. - 3.4 eV C. - 6.04 eV D. - 13.6 eV
Added by Leah B.
Step 1
6 eV. The energy of an electron in the nth excited state of a hydrogen atom is given by the formula: En = -13.6/n^2 eV where n is the principal quantum number. For the 2nd excited state, n = 3. Plugging in the value of n, we get: E3 = -13.6/3^2 = -1.51 Show more…
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The energy of a hydrogen atom in its ground state is -13.6 eV . The energy of the level corresponding to the quantum number n = 2 (first excited state) in the hydrogen atom is (a) – 2.72 eV (b) – 0.85 eV (c) – 0.54 eV (d) – 3.4 eV
Deepak J.
Energy of $\mathrm{H}$ -atom in the ground state is $-13.6 \mathrm{eV}$, hence energy in the second excited state is: (a) $-6.8 \mathrm{eV}$ (b) $-3.4 \mathrm{eV}$ (c) $-1.51 \mathrm{eV}$ (d) $-4.53 \mathrm{eV}$
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