00:01
In this question, it is given that for null hypothesis, p is less than equals to 0 .58 and for alternative hypothesis, p is greater than 0 .58.
00:18
Now the value of sample space n is given 1149 and p cap is 0 .6185 and the significance level is given as 2 .5 % which can be written as 25 over 100 which is 0 .025.
00:49
So this is the significance level now.
00:52
Now in the first step, let us write down the null hypothesis and alternative hypothesis.
01:02
So alternative hypothesis p is greater than 0 .58.
01:07
So in the next step, we will write down the significance level alpha which is 0 .025.
01:16
Now the test statistic is given by statistic that is given by z equals to p cap minus p over square root of p minus q over n because p is 0 .58.
01:38
So therefore, q will be 1 minus p which is 1 minus 0 .58 that is equals to 0 .42.
01:47
Now substituting the values in the formula of the test statistic that is z equals to p cap minus p.
01:54
So z equals to 0 .6185 minus 0 .58...