00:01
In this problem, we have been given information about how many students in a certain school are taking a math class and how many of them are taking an english class.
00:08
Now, first of all, we need to find the probability that a randomly select a student is taking a math class or an english class.
00:14
So let us consider n to be the event that a student is taking a math class and e to be the event that a student is taking an english class.
00:23
So we need to determine the probability of m union e because union represents or.
00:28
Now using the addition law of probability, this is equal to p of m plus p of e minus p of m intersection e.
00:40
Now p of m, that is the probability that a student is taking a math class.
00:45
Now 75 % of the students are taking a math class, so this probability is 75 % or 75 by 100 or 0 .75.
00:53
Also it is said that 72 % of students are taking an english class.
00:56
So the probability of the event e is 72%, which is 72 by 100 or 0 .72.
01:04
And intersection represents and, so p of m intersection e is the probability that a student is taking both a math class and an english class...