In a magnetic field of magnitude 3 T given in Teslas and directed from left to right, a positron moves (The positron is the antiparticle of the electron, which means that it is a particle with the same mass as that of the electron but with a positive electrical charge.) with a speed of 5.1 x 10^2 m/s. Because of this, the particle experiences a magnetic force of 3.57 x 10^-17 N, directed out of the plane of the page. What is the angle (in degrees) between the velocity vector and the magnetic field?
Added by Mary J.
Step 1
57 \times 10^{-17} \, N \), \( q = 1.6 \times 10^{-19} \, C \), \( v = 5.1 \times 10^{2} \, m/s \), and \( B = 3 \, T \). Show more…
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