In a manufacturing process 15 units are randomly selected each day from the production line to check the percent defective of the process. Based on historical information, the probability of a defective unit is 0.05. Management has decided to stop the production line for inspection any time a sample of 15 units yields two or more defectives. what is the probability that on any given day the production process will be stopped?
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We are given that the probability of a defective unit is 0.05, so the probability of a non-defective unit is 1 - 0.05 = 0.95. Show more…
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During a manufacturing process, 15 units are randomly selected each day from the production line to check the percent defective. From historical information it is known that the probability of a defective unit is $0.05 .$ Any time 2 or more defectives are found in the sample of $15,$ the process is stopped. This procedure is used to provide a signal in case the probability of a defective has increased. (a) What is the probability that on any given day the production process will be stopped? (Assume $5 \%$ defective.) (b) Suppose that the probability of a defective has increased to $0.07 .$ What is the probability that on any given day the production process will not be stopped?
Sheryl E.
During manufacturing process 15 units are randomly selected each day from the production line check the percent defective From historical information it known thatthe probability defective unit 0.05 _ Any time that two more defectives are foundin the sample of 15, the process is stopped_ This procedure used provide signal incase the probability defective has increased (a) What is the probability that any given day the production rocess Will stopped? (Assume 5% defective.) (b) Suppose that the probability defective has increased to 0.07 _ What is the probability that any given day the production process Will not stopped?
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