In a plane electromagnetic wave , the electric field oscillates sinusoidally at a frequency of 2*10^10 Hz and amplitude 48 V/m . What is the wavelenght of the wave and amplitude of the oscillating magnitude.
Added by Shirlin S.
Step 1
Given: Frequency, f = 2*10^10 Hz Speed of light, c = 3*10^8 m/s Using the formula: λ = c / f Substitute the values: λ = 3*10^8 / 2*10^10 λ = 1.5*10^-2 Therefore, the wavelength of the wave is 0.015 meters. Show more…
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