4. In a plant, solid particles (i.e. ash) are carried away...

Name: 4. In a plant, solid particles (i.e. ash) are carried away by the stack gas and causes air pollution. What should be diameter of the stack to prevent pollution if the flow rate of the gas is 10 m³/s? Take the stack gas as air. The density and diameter of the solid particles are 680 kg/m³ and 1.25 mm, respectively.
Uploaded: 2023-10-20T00:50:02-08:00
Duration: 5 min 42 s
Channel: Supreeta N
Description: 4. In a plant, solid particles (i.e. ash) are carried away by the stack gas and causes air pollution. What should be diameter of the stack to prevent pollution if the flow rate of the gas is 10 m³/s? Take the stack gas as air. The density and diameter of the solid particles are 680 kg/m³ and 1.25 mm, respectively.

4. In a plant, solid particles (i.e. ash) are carried away by the stack gas and causes air pollution. What should be diameter of the stack to prevent pollution if the flow rate of the gas is 10 m³/s? Take the stack gas as air. The density and diameter of the solid particles are 680 kg/m³ and 1.25 mm, respectively.

Transcript

00:01 Hello students, in this question they have given the sampling time is 8 minutes, velocity of the gas is 15 meter per second, area of the probe is 5 .07 centimeter square and the mass of the particulates is given as 0 .430 gram and we are asked to calculate the concentration of particulates in microgram per meter cube.

00:25 For this the formula concentration of the particulates is equal to mass by volume.

00:30 So volume we have to calculate, volume is equal to gas velocity in meter per second into the sampling time into the area of the probe.

00:46 So area of the probe in meter square.

00:51 So first volume is equal to, volume we can calculate as 15 meter per second into sample time is 8 minutes which can be converted into seconds, this has to be given in seconds therefore 4 into 60 into area of the probe is 5 .07 centimeter square therefore it has to be converted into meter therefore 10 power minus 4.

01:19 So on calculating this we are getting the volume is equal to 3 .65 meter cube.

01:31 Then the concentration of the mass, concentration of the particulates given is m by v, m is given data m by v into 10 power 6 which is equal to 0 .430 gram divided by 3 .65 meter cube and it has to be converted into microgram therefore 10 power 6 therefore on calculating this we will be getting 117808 .23 microgram per meter cube.

02:05 So this is the concentration of the particulates, concentration of the particulates is 117808 .23 microgram per meter cube.

02:18 Next we have to calculate the total emissions, total mass emissions per day in kg...

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