Question

In a random sample of 352 observations, $\bar{p}$ = 0.4. What lower bound of a 90% confidence interval for $p$? Round to four decimal places for all your calculations, including the FINAL answer. Include the zero before the decimal place. E.g., 0.1234

          In a random sample of 352 observations, $\bar{p}$ = 0.4. What lower bound of a 90% confidence interval for $p$?

Round to four decimal places for all your calculations, including the FINAL answer.

Include the zero before the decimal place. E.g., 0.1234

In a random sample of 352 observations, p̅ = 0.4. What lower bound of a 90% confidence interval for $p$?

Round to four decimal places for all your calculations, including the FINAL answer.

Include the zero before the decimal place. E.g., 0.1234

Added by Lance V.

Principles of Economics

Gregory Mankiw 8th Edition

Instant Answer

Solved by Expert Christopher Dzorkpata

10/25/2021

Step 1

The standard error (SE) can be calculated using the formula: SE = sqrt((p*(1-p))/n) where p = 0.4 (the sample proportion) and n = 352 (the sample size). SE = sqrt((0.4*(1-0.4))/352) SE = sqrt((0.24)/352) SE = sqrt(0.000681818) SE ≈ 0.0261 Show more…

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In a random sample of 352 observations.p=0.4.What lower bound of a 90% confidence interval forp? Round to four decimal places for all your calculations,including the FINAL answer Include the zero before the decimal place.E.g.,0.1234