In a recent study, which of the participants below excluded from their activity the free-riders who chose not to collaborate in a prior activity?
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Dan Ariely and colleagues have conducted some extremely interesting studies on cheating (see, for example Mazar, Amir, & Ariely, 2008). To provide an opportunity for cheating, participants are given a packet of problems and told they will be paid $0.50 for each correct answer. The experiment is setup, however, so that the participant doesn't have to turn in their work, they simply have to state how many problems they solved to get paid. This provides a prime opportunity to cheat to earn extra money. In previous tests where the problems are properly scored, so no cheating, Ariely and colleagues found that scores are normally distributed: μ = 3.3, σ = 1.0. Here is a list of scores for participants who knew that their work would not be checked. Which of these would you suspect of cheating? Why? a. Participant 1: X = 4 b. Participant 2: X = 6 c. Participant 3: X = 7 d. Participant 4: X = 0
David N.
Imagine that you re-ran the Asch line study today. Who would be the LEAST likely to conform to the confederates giving wrong answers? 1.People who had to be the first to report their answers. 2.People who participated in the Asch line study with confederates consisting of close others, such as important friends and family members. 3.People who had to listen to a recording of confederates giving wrong answers instead of being with the confederates in person. 4.People who completed a more difficult version of the task.
Jerelyn N.
One experiment contrasted responses to ”prediction-request” and to ”request-only” treatments, in order to answer two research questions: (i) Can people predict how well they will behave? (ii) Do their predictions influence their behavior? In the prediction-request group, subjects were first asked to predict whether they would agree to do some volunteer work. Then they were requested to do the work. In the request-only group, the subjects were requested to do the work; they were not asked to make predictions beforehand. In parts a-c, a two-sample z-test may or may not be legitimate. If it is legitimiate, make it. If not, why not? (a) 46 residents of Bloomington, Indiana, were chosen at random for the ”prediction-request” treatment. They were called and asked to predict ”whether they would agree to spend three hours collecting for the American Cancer Society if contacted over the phone with such a request”. 22 out of the 46 said that they would. Another 46 residents of that town were chosen at random for the ”request-only” treatment. They were requested to spend three hours collecting for the American Cancer Society. Only 2 out of 46 agreed to do it. Can the difference between 22/46 and 2/46 be due to chance? What do the data say about the research questions (i) and (ii)?
Anand J.
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