Question

In a single-effect evaporator, 10\% NaOH solution is concentrated and 40\% NaOH solution is obtained. The feed flow rate is 1000 kg/h. The latent heat of evaporation of steam used as a heating medium is 500 kcal/kg. The enthalpy of the superheated steam leaving the evaporator is 600 kcal/kg. The enthalpy of the dilute feed solution is 25 kcal/kg, while that of the concentrated solution is 100 kcal/kg. Calculate the steam consumption.

          In a single-effect evaporator, 10\% NaOH solution is concentrated and 40\% NaOH solution is obtained.
The feed flow rate is 1000 kg/h. The latent heat of evaporation of steam used as a heating medium is
500 kcal/kg. The enthalpy of the superheated steam leaving the evaporator is 600 kcal/kg. The enthalpy
of the dilute feed solution is 25 kcal/kg, while that of the concentrated solution is 100 kcal/kg. Calculate
the steam consumption.
        
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In a single-effect evaporator, 10% NaOH solution is concentrated and 40% NaOH solution is obtained.
The feed flow rate is 1000 kg/h. The latent heat of evaporation of steam used as a heating medium is
500 kcal/kg. The enthalpy of the superheated steam leaving the evaporator is 600 kcal/kg. The enthalpy
of the dilute feed solution is 25 kcal/kg, while that of the concentrated solution is 100 kcal/kg. Calculate
the steam consumption.

Added by Derek U.

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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In a single-effect evaporator, 10% NaOH solution is concentrated and 40% NaOH solution is obtained. The feed flow rate is 1000 kg/h. The latent heat of evaporation of steam used as a heating medium is 500 kcal/kg. The enthalpy of the superheated steam leaving the evaporator is 600 kcal/kg. The enthalpy of the dilute feed solution is 25 kcal/kg, while that of the concentrated solution is 100 kcal/kg. Calculate the steam consumption.
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Transcript

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00:01 So over here material balance material balance formula if you write material balance that is f is equals to v plus b.
00:09 Okay, so here 10 ,000 is equals to v plus b.
00:14 This is our equation number one.
00:16 Okay, now noh and naoh balance if you do naoh balance that will be 20 % of f right 20 % of f is equals to 45 % of p.
00:29 So from here 20 divided by 100 20 % multiplied by 10 ,000 is equals to 45 % that is 45 by 100 multiplied by p.
00:39 So from here we got the p value was 40 ,000 divided by 9 kg per hour.
00:45 Okay, now now v value if you see v is equals to 10 ,000 minus 40 ,000 divided by n and divided by 9 that gives rise to 50 ,000 divided by 9...
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