0:00
Hello students.
00:02
So in this question we have a problem.
00:04
So yeah starting from its solution.
00:08
That is, no2, no2 gives or decomposes into no plus half o2.
00:20
So we know that 1 by no2, 1 by concentration of no2 versus time versus time graph.
00:31
So the slope is at, the slope is at over 0 .761 molar inverse, second inverse.
00:43
And intercept is at, intercept is at 3 .40 molar inverse.
00:58
So the graph is just like this.
01:03
Where if this is the concentration of 1 by n or n o concentration and this is the time so this is the slope like this and and this is the slope where k is the slope where k is the slope or constant and this is the one over a not one over a not value so from the unit of slope, we can first consider second order reaction because slope has a unit.
01:46
So it gives us information that is the second order reaction is there.
01:54
Second order reaction is there...