Question

In a survey of 240 students, 85% said they enjoyed the classes they were taking. What is the margin of error for those results? State your answer as a percent rounded to the nearest tenth of a percent, but do not include a % symbol or "+/-" in your response.

Name: in a survey of 240 students 85 said they enjoyed the classes they were taking what is the margin of error for those results state your answer as a percent rounded to the nearest tenth of a p 22054
Uploaded: 2023-06-01T01:17:00-08:00
Duration: 1 min 23 s
Channel: Qudsiya Anis
Description: in a survey of 240 students 85 said they enjoyed the classes they were taking what is the margin of error for those results state your answer as a percent rounded to the nearest tenth of a p 22054

          In a survey of 240 students, 85% said they enjoyed the classes they were taking.
What is the margin of error for those results?
State your answer as a percent rounded to the nearest tenth of a percent, but do not include a % symbol or "+/-" in your response.

in a survey of 240 students 85 said they enjoyed the classes they were taking what is the margin of error for those results state your answer as a percent rounded to the nearest tenth of a p 22054

Added by David C.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Qudsiya Anis

06/01/2023

Step 1

The standard deviation for a proportion is given by: $$ \sigma = \sqrt{\frac{p(1-p)}{n}} $$ where $p$ is the sample proportion and $n$ is the sample size. In this case, $p = 0.85$ and $n = 240$. $$ \sigma = \sqrt{\frac{0.85(1-0.85)}{240}} = \sqrt{\frac{0.85 \times Show more…

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In a survey of 240 students, 85% said they enjoyed the classes they were taking. What is the margin of error for those results? State your answer as a percent rounded to the nearest tenth of a percent, but do not include a % symbol or "+/-" in your response.