In a system atwoods machine of two masses hanging on...

In a system (Atwood's machine) of two masses hanging on inextensible and massless threads, running through a pulley, we have a mass difference that causes an acceleration. Graphing the acceleration as a function of the overload or mass difference, we obtained the following linear regression: y = 280x + 0.0257 Find the friction of the pulley.

Transcript

00:01 Hello students, in this question we are given that two masses hanging on inextensible and massless threads running through a pulley and we are given there is a difference of the masses and again graph of acceleration as a function of the mass difference is obtained in this portion and which is given to us as y is equal to 280 x plus 0 .0 to 5 .7.

00:28 So this is the function of isolation as a function of mass difference given to us.

00:34 Here x is the mass difference and y is the isolation.

00:38 So we have to calculate the friction of the pulley in this question.

00:44 So first of all on comparing with the pulley equation, on comparing with the pulley equation, simple pulley equation in which acceleration is equal to mass difference m2 minus m1 multiplied by the gravity divided by m1 plus m2 plus mass equivalent minus of f k where f is the force of friction fk again divided by m1 plus m2 plus mq so on comparing this first of all let us compare these two equation and according to this equation are 280 first of all 280 is equal to gravity divided by m1 plus m2 plus m equation so 280 is equal to on this 280 we have here we have this term and in terms of 0 .057 we have this term so we are comparing our both equations so 280 is equal to m1 280 is equal to g divided by m1 plus m2 plus m equivalent from this upon cross multiplying m1 plus m equivalent is coming out to be g divided by 2 .2 that would be equal to 9 .8 divided by 280 which is approximated to 0 .035 so we have obtained the result m1 plus m2 plus m equivalent is equal to 0 .035 so we have obtained the result m1 plus m2 plus m equivalent is equal to 0.

02:35 0 .035 in this case.

02:38 Now on comparing this term that is 0 .0257 is equal to force of friction plus m1 plus m2 plus m equivalent...

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