00:01
Hey there, welcome to numerate.
00:03
We are looking at the effectiveness of garlic for lowering cholesterol here.
00:09
So we have the changes in levels of ldl cholesterol with the mean of 3 .5, standard deviation of 16 .6.
00:18
So what is the best point estimate for the population mean of the net change? so the best point to estimate the bpe for the population means.
00:30
Mean is basically the sample mean, which is given to us as 3 .5.
00:41
For part a, part b over here, so let me change that.
00:48
What we have here is constructing 95 % confidence interval for the mean that change after the garlic treatment.
00:58
So what we have here for our equation is confidence interval equals our sample mean plus and minus our t critical value, multiplied by our standard deviation divided by the square root of n.
01:14
So our sample mean here is 3 .5, plus and minus our critical value, based off our 95 % confidence, is around 2 .02, multiplied by our standard deviation of 16 .6, divided by the square root of 42, our sample size.
01:36
So what we can do here is calculate and write out our confidence interval...