In a test of the effectiveness of garlic for lowering cholesterol,48 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (beforeminus−after) in their levels of LDL cholesterol (in mg/dL) have a mean of 4.2 and a standard deviation of 16.8 Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol?
Added by Michael T.
Step 1
The standard error of the mean is the standard deviation divided by the square root of the sample size. In this case, the standard deviation is 16.8 and the sample size is 48. So, the standard error of the mean is 16.8 / sqrt(48) = 2.43. Show more…
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