00:01
Let me write the reaction first of all.
00:01
This is clo3 negative aquas plus 5 cl negative aquas plus 6 h positive ion aquas.
00:14
Okay.
00:16
And now this gives 3 cl2 gas plus 3h2o liquid.
00:30
Okay.
00:33
So now the rate of react that is directly proportional to concentration of reactant.
00:40
This is what rate equation is.
00:41
Okay, so we have this chlorate ion concentration multiplied by a concentration of chloride multiplied by concentration of h positive ion.
00:53
Or this can be written as that rate is equals to k, k is the rate constant multiplied by a concentration of chlorate, raise to power m consider the order as m n o okay raised to power m now this is cl negative raise to power n and this is h positive raise to power o okay so these are the order which we have to calculate here because they are actually found out by experimental methods right so now what we can do here see i have attached this table here which we have given in the question with the help of this table we can consider the equations okay so now this is experiment one two three four okay and accordingly we can consider equation first second third fourth okay so now by wait let me write this so we can write here that rate if i consider experiment first okay so for experiment first so i can write that 1 .00 is equals to so i'm not writing the units okay so 1 .00 is equals to k rate constant multiplied by concentration of chlorate so that is 0 .632 raise to power m 0 .442 raise to power n and 0 .0 .0 .049 raised to power and 0 .0 .049 raised to power and and and okay and similarly experiment 2 so this will be 1 .50 is equals to k multiplied by so we have 0 .948 raised to power m 0 .442 raise to power n and we have 0 .0 .049 raised to power n okay if i consider the equation this is first equation and this is second equation okay so now by first and second equation so or we can divide these equations okay so we can write here by second divide by first okay so this will be 1 .50 divide by 1 that is equals to so this is 0 .948 raise to power 5 .5.
03:49
M and now this is 0 .492 raise to power n and this is 0 .4049 raised to power n.
04:05
Okay? divided by so this will be k so see k to k will be cancelled out okay so can i ignore this so this will be 0 .632 raised to power and 0 .442 raised to power n and this is 0 .049 raised to power n.
04:31
Now you can clearly see that this to this and this to this will be cancelled out.
04:36
So we are left with these.
04:39
Okay.
04:40
So this will be 0.
04:43
Okay.
04:44
So now see this is 1 .00 right? so now this will be 1 .00 right? so now this will be 1 .4.
04:54
5 is equals to so now this will be 0 .948 divided by 0 .632 raised to power m since the powers are same so they can be considered common okay on solving this will be 1 .5 is equal to 1 .5 raised to power m okay so now since the base value is same so this will be m is equals to 1 .1 and in this way with respect to this m we have first order okay now similarly we can find out for n and o okay so now let me consider experiment two and four okay so now by or let me write the equations so this will be for experiment two so you know that this will be 1 .50 is equal 2 so concentration of 0 .948 raise to power m 0 .442 raise to power n concentration of 0 .0 .049 raised to power n so similarly experiment fourth okay so this will be we have 3 .00 that is equals to concentration 0 .948 raise to power m concentration of 0 .884 raised to power n and this will be 0 .049 raise to power n.
06:53
Okay.
06:54
So now by let us consider this as equation number third and this is equation number fourth.
07:03
Okay.
07:03
So by four divide by third.
07:10
So this will be 3 .00 divided by 1 .50.
07:16
That's equal to now this to this will be cancelled out right and this to this will be cancelled out.
07:22
So we are left with 0 .884 divided by 0 .442 and since the powers are same so we can take this common...