Question

In all known cells, the metabolic process known as glycolysis breaks down glucose into two molecules of pyruvic acid: C6H12O6(s) → 2 C3H4O3(l) + 2 H2(g) ΔHº = 105.4 kJ If the cells are under oxidative stress (aren't getting enough oxygen), the pyruvic acid is further broken down into lactic acid: C3H4O3(l) + H2(g) → C3H6O3(s) ΔHº = -109.58 kJ What is the enthalpy change for the formation of glucose from two molecules of lactic acid at 25 ºC? (Be sure to include units!) 2 C3H6O3(s) → C6H12O6(s) ΔHº = ?

          In all known cells, the metabolic process known as glycolysis breaks down glucose into two molecules of pyruvic acid:
C6H12O6(s) → 2 C3H4O3(l) + 2 H2(g)      ΔHº = 105.4 kJ

If the cells are under oxidative stress (aren't getting enough oxygen), the pyruvic acid is further broken down into lactic acid:
C3H4O3(l) + H2(g) → C3H6O3(s)      ΔHº = -109.58 kJ

What is the enthalpy change for the formation of glucose from two molecules of lactic acid at 25 ºC? (Be sure to include units!)
2 C3H6O3(s) → C6H12O6(s)     
ΔHº = ?

Added by Lourdes M.

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