00:01
Okay, so this question is asking us about an acid -based titration between n -a -o -h and h -2 -s -o -4.
00:07
So the first thing that we're going to need to do to know how many milliliters are needed to neutralize it is write our balanced equation.
00:16
And so in order to do that, let's start by writing out what we know.
00:20
So we know that we have n -a -o -h and h -2 -s -4 being neutralized.
00:33
And since this is an acid -based reaction, we're just going to fly.
00:35
Flip it.
00:35
And so we know that we're going to get water since it's acid -based neutralization and n -a -s -o -4.
00:53
And so we know that because acid bases were, tetrations, we're always going to form water, and then we just switched our bases, so -4, and n -a.
01:02
And so now we need to balance this.
01:04
And so we see that we have two n -a's on this side.
01:08
Why do we have two n -a's? because s -o -4, so four has a negative two charge, negative two, and an a only has a plus one charge.
01:17
So we're going to need two sodium ions to neutralize the negative two charge of the sulfate ion.
01:25
And so we need to balance this.
01:27
And so we have two sodiums on this side.
01:29
So we're going to have to put a two in front of here so we can balance our sodiums.
01:33
Well, and then in order to balance all of our hydrogens and oxygens, we're going to have to put a2 in front of this water.
01:41
And now solving for that and making sure all of our ions are equal, we find that this is our balanced equation.
01:48
And so now that we have our balanced equation, we can start by start trying to find out how many moles of our solutions we have.
01:55
And so we're trying to find out how many milliliters of the naoh solution we need.
01:59
So let's start by looking at our h2so4.
02:01
So it tells us that we had 20 milliliters of this h2so4.
02:06
20 milliliters is the same as 0 .02 liters.
02:10
You just divide by 1 ,000 to give from milliliters to liters.
02:13
And it says that we had a 0 .15 molar solution...