00:01
Hi, i'm david and i'm here to help you answer your question.
00:03
Now let me bring up your question here.
00:06
In the question here, we are going to discuss about the confidence interval for the difference between the two means, as well as the confidence, the hybrid testing.
00:16
Here first, the confidence interval for the mu1 minus the mu 2, it will be the x bar 1 minus the x bar 2, plus and minus the critical value t star, 10 with the boon, boon standard division times when the 1 over n1 plus 1 over n2.
00:35
Now in this question here we're given the n1 equal to the 35 the x -par 1 equal to the 13 .25 the s1 square equal to the 36 n2 equal to the 32 the x par 2 equal to the 10 .13 the s2 square equal to 2 the 30 and from here the first step i will need to find the pool standard division sp it will equal to the square root of the n1 minus 1 time with the s1 square plus n2 minus 1 time with the s2 square dividing by the n1 plus n2 minus 2 now if we're clicking the value we will have n1 minus 1 will be the 34 time with the s1 square 36 plus and 2 minus 1 will be the 31 times the 2 square will be the 30 other the 35 plus 32 minus 2 and if we compute 34 times 36 plus 31 times 30 dividing by the 35 plus 32 minus 2 taking the square root get equal to the 5 .7 56 57.
02:03
And then the next step we will need to find the critical value t star.
02:09
T star just equal to the t when the degree freedom equal to this quantity here, it will equal to the 65 and the unfar under 90 % confidence and far equal to the 10 % the value equal to the 5 % which is equal to the zbomzo 5.
02:28
Now to find this value i will use the distribution with the 65 degree freedom and at the level 0 .05, then we can equal to the 1 .669.
02:44
And from here we are ready to find the 90 % confidence interval for the mu1 minus the mu2.
02:53
We have the first point estimate, the question also asked to find the point estimate.
02:58
So the point estimate it will equal to the xpa 1 minus the x bar 2, it will equal to the 13 .25 minus the 10 .13 .13.
03:17
And then we get equal to the 3 .12.
03:23
Therefore we have the xpa 1 minus xxp2.
03:25
It will equal to the 3 .12 plus and minus the test the critical value.
03:32
Time with the sp will be the 5 .7 times with the square root of the 1 over 35 plus 1 over the 32.
03:45
If we compute the quantity on the right, we will have the 1 over 35 plus 1 over 32, taking the square root times 5 .7 times 1 .7 times 1...