The half-reaction is:
$$\text{Zn (s)} \rightarrow \text{Zn}^{2+} (aq) + 2e^-$$
b) At the cathode, reduction occurs. The half-reaction is:
$$\text{Fe}^{3+} (aq) + e^- \rightarrow \text{Fe}^{2+} (aq)$$
c) To balance the redox reaction, we need to multiply the
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