00:01
Okay, for this problem we have four grams of an impure sodium chloride salt that's dissolved in water and then treated with excess silver nitrate so we would have nacl plus agno3 goes to silver chloride, which is our precipitate plus sodium nitrate, which is going to be still dissolved in solution.
00:21
Okay, so what we need to do is we need to figure out how many grams of sodium chloride would produce 7 .55 grams of silver chloride.
00:30
So silver has a molar mass of 108, chlorine is 35, so 108 plus 35 is 143.
00:39
We also need to find our molar mass for sodium chloride, so it's 23 plus 35, so 58 and well, we're at it because maybe we don't need that.
00:50
Okay, so let's, our coefficients, this is balanced right now, so they're all 1, so we just need to find our moles of silver chloride.
00:59
So 7 .55 divided by 143 is 0 .0528 moles, so that's for a coefficient of 1, or 1 right here...