In an ideal 1:8 step-up transformer, the primary power is 10 kW and the secondary current is 25 A. The primary voltage is A : 6.25 V. B : 25,600 V. C : 3200 V. D : 400 V. E : 50 V.
Added by Danny I.
Step 1
We also know that in an ideal transformer, the power in the primary coil (P1) equals the power in the secondary coil (P2), or P1 = P2. Given that the primary power P1 is 10 kW, we can find the primary current I1 by rearranging the power equation to I1 = P1/V1. Show more…
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