Question

In an open-tube manometer (see the figure below), the absolute pressure in the container of gas on the left is 2.10 × 10^5 Pa. If atmospheric pressure is 1.01 × 10^5 Pa and the liquid in the manometer is mercury (density 1.36 × 10^4 kg/m^3), what will be the difference in the heights of the left and right columns of liquid?

Name: In an open-tube manometer (see the figure below), the absolute pressure in the container of gas on the left is 2.10 × 10^5 Pa. If atmospheric pressure is 1.01 × 10^5 Pa and the liquid in the manometer is mercury (density 1.36 × 10^4 kg/m^3), what will be the difference in the heights of the left and right columns of liquid?
Uploaded: 2021-04-19T21:07:16-08:00
Duration: 2 min 39 s
Channel: Nishant Kumar
Description: In an open-tube manometer (see the figure below), the absolute pressure in the container of gas on the left is 2.10 × 10^5 Pa. If atmospheric pressure is 1.01 × 10^5 Pa and the liquid in the manometer is mercury (density 1.36 × 10^4 kg/m^3), what will be the difference in the heights of the left and right columns of liquid?

          In an open-tube manometer (see the figure below), the absolute pressure in the container of gas on the left is 2.10 × 10^5 Pa. If atmospheric pressure is 1.01 × 10^5 Pa and the liquid in the manometer is mercury (density 1.36 × 10^4 kg/m^3), what will be the difference in the heights of the left and right columns of liquid?

In an open-tube manometer (see the figure below), the absolute pressure in the container of gas on the left is 2.10 × 10^5 Pa. If atmospheric pressure is 1.01 × 10^5 Pa and the liquid in the manometer is mercury (density 1.36 × 10^4 kg/m^3), what will be the difference in the heights of the left and right columns of liquid?

Added by Sacul R.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Nishant Kumar

04/19/2021

Step 1

Given: Absolute pressure in the container of gas on the left = 2.10×10^5 Pa Atmospheric pressure = 1.01×10^5 Pa Pressure difference = Absolute pressure - Atmospheric pressure Pressure difference = 2.10×10^5 Pa - 1.01×10^5 Pa Pressure difference = 1.09×10^5 Pa Show more…

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In an open-tube manometer (see the figure below), the absolute pressure in the container of gas on the left is 2.10×10^5 Pa. If atmospheric pressure is 1.01×10^5 Pa and the liquid in the manometer is mercury (density 1.36×10^4 kg/m^3), what will be the difference in the heights of the left and right columns of liquid?