In a vacuum, two particles have charges of $q_1$ and $q_2$, where $q_1 = +2.8 \mu C$. They are separated by a distance of 0.23 m, and particle 1 experiences an attractive force of 4.7 N. What is the value of $q_2$, with its sign?
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Coulomb's Law states that the force between two charged particles is given by the equation: F = k * (|q1| * |q2|) / r^2 where F is the force, k is the electrostatic constant (9.0E9 Nm^2/C^2), |q1| and |q2| are the magnitudes of the charges, and r is the distance Show more…
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