Question

Here is the function prototype: void AvergeOfThree (int, int, int, double); //input: two integer values //input/output: one integer and one double //Asks and gets an integer from the user and stores it in the "value at" the third parameter //Calculate the average of the 3 integers and store the result in the "value at" the fourth parameter. void AvergeOfThree (int, int, int, double);

          Here is the function prototype: void AvergeOfThree (int, int, int*, double*);
//input: two integer values
//input/output: one integer and one double
//Asks and gets an integer from the user and stores it in the "value at" the third
parameter
//Calculate the average of the 3 integers and store the result in the "value at" the
fourth parameter.
void AvergeOfThree (int, int, int*, double*);

Here is the function prototype: void AvergeOfThree (int, int, int*, double*);
//input: two integer values
//input/output: one integer and one double
//Asks and gets an integer from the user and stores it in the "value at" the third
parameter
//Calculate the average of the 3 integers and store the result in the "value at" the
fourth parameter.
void AvergeOfThree (int, int, int*, double*);

Added by Dana H.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Instant Answer

Solved by Expert Md.Daniyal Arshad

Step 1

The function is named "AverageOfThree" and it takes two integer values as input. Show more…

Show all steps

Thanks for your feedback!

Here is the function prototype: void AverageOfThree(int, int, int*, double*) //input: two integer values //input/output: one integer and one double //Asks and gets an integer from the user and stores it in the "value at" the third parameter //Calculate the average of the 3 integers and store the result in the value at the fourth parameter. void AverageOfThree(int, int, int*, double*);