Question

In calculating significance tests for comparing two proportions, the estimate of the overall population proportion of successes from two samples is ______. (Note: $X_1$ and $X_2$ are the numbers of successes from Populations 1 and 2, respectively, and $n_1$ and $n_2$ are the sample sizes from Populations 1 and 2, respectively.) $\hat{p} = \frac{X_1+X_2}{n_1+n_2}$ $\hat{p} = \frac{X_1+X_2+2}{n_1+n_2+4}$ $\hat{p} = \frac{X_1+X_2}{n_1+n_2+4}$

Name: in calculating significance tests for comparing two proportions the estimate of the overall population proportion of successes from two samples is note x1 and x2 are the numbers of 15485
Uploaded: 2022-05-19T09:53:57-08:00
Duration: 42 s
Channel: Rashmi Sinha
Description: in calculating significance tests for comparing two proportions the estimate of the overall population proportion of successes from two samples is note x1 and x2 are the numbers of 15485

          In calculating significance tests for comparing two proportions, the estimate of the overall population proportion of successes from two samples is ______. (Note: $X_1$ and $X_2$ are the numbers of successes from Populations 1 and 2, respectively, and $n_1$ and $n_2$ are the sample sizes from Populations 1 and 2, respectively.)
$\hat{p} = \frac{X_1+X_2}{n_1+n_2}$
$\hat{p} = \frac{X_1+X_2+2}{n_1+n_2+4}$
$\hat{p} = \frac{X_1+X_2}{n_1+n_2+4}$

in calculating significance tests for comparing two proportions the estimate of the overall population proportion of successes from two samples is note x1 and x2 are the numbers of 15485

Added by Raymond M.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Rashmi Sinha

05/19/2022

Step 1

This is often referred to as the "pooled proportion" or "pooled estimate of p". Step 2: Let $X_1$ be the number of successes from Population 1 and $n_1$ be the sample size from Population 1. The sample proportion for Population 1 is $\hat{p}_1 = Show more…

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In calculating significance tests for comparing two proportions, the estimate of the overall population proportion of successes from two samples is ______. (Note: $X_1$ and $X_2$ are the numbers of successes from Populations 1 and 2, respectively, and $n_1$ and $n_2$ are the sample sizes from Populations 1 and 2, respectively.) $\hat{p} = \frac{X_1+X_2}{n_1+n_2}$ $\hat{p} = \frac{X_1+X_2+2}{n_1+n_2+4}$ $\hat{p} = \frac{X_1+X_2}{n_1+n_2+4}$