In Exercises 23-32, find the $ x $- and $ y $-intercepts of the graph of the equation. $ y^2 = x+1 $
Added by Patrick P.
Step 1
To do this, we'll set y = 0 and solve for x. $ (0)^2 = x + 1 $ $ 0 = x + 1 $ $ x = -1 $ So, the x-intercept is $ \boxed{-1} $. Show more…
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