Since the two resistors with resistance $R$ are in parallel, their equivalent resistance is given by:
$$\frac{1}{R_{eq}} = \frac{1}{R} + \frac{1}{R} = \frac{2}{R}$$
So, $R_{eq} = \frac{R}{2}$. Now, the total resistance in the circuit is $R_{1} + R_{eq} = R_{1} +
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