In Figure 2, a link holds up the weight and forces pulled...

In Figure 2, a link holds up the weight and forces pulled down by a cable attached to the box. y 3m 30$^\circ$ F = 200N 15m 0 1.5m x Figure 2 a) Sketch the free-body diagram of the structure. [15 Marks] b) Calculate the resultant force and vector corresponding horizontal and vertical axis. [10 Marks] c) Calculate the cable force vector for the string. [15 Marks] (CLO1-PLO1:C2) [Total: 40 Marks]

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Transcript

00:01 Hi there, so for this problem, we have the situation that is shown in here.

00:05 Now, the resulting force for this is along the y direction about here.

00:15 And we're told that this, let's call this the net force, and the magnitude for that force is given, and that is equal to 530 newtimes.

00:29 So with that set, we need to determine.

00:34 Mean the force f in magnitude and the angle theta, okay? so first of all, you can see from the figure that the net force in vector form is just the force f in vector form plus the force that we have in here.

00:55 So that force it has two components.

00:57 The f component is negative, so that will be then in here, 700 times minus the cosine of 15 degrees.

01:09 And this, the y component is also negative because it's pointing downward and that will be the sign of 15 degrees.

01:20 Okay.

01:21 Then with that said, oh, this is in the x direction and this in the y direction.

01:27 Now, what we need to do in this case is to solve for the force f.

01:31 So we pass these to terms to the left side.

01:37 So we'll obtain that that is just the net force that is 530.

01:44 This only is in the wide direction and it is positive.

01:48 And if we pass everything to, well, the force that is being applied with 15 degrees to the left, we will obtain that everything passed to be positive...

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