00:01
In this problem, we have been given the two blocks of masses 10 kilograms and 4 kilograms respectively, provided that the surface on which m1 is resting, that's having the static friction coefficient as 0 .5 and the kinetic friction coefficient as 0 .3.
00:20
So initially they are at rest, and now we have to figure out the acceleration when the system is released from rest.
00:27
So as we can observe during the free body diagram there will be weight of the two objects in the downward direction and that will be obtained by multiplying mass with the acceleration due to gravity so when we multiply m1 with g we're gonna get the weight as 98 neutins similarly by multiplying four times 9 .8 we get 39 .2 as the weight of m2 so there will be tension force and there will be normal force on this m1 there will be friction force.
01:02
So when the block is released from rest, that means the friction force acting at that instant, that will be the static friction.
01:10
So we observe the magnitude of static friction as the coefficient of static friction times the normal force.
01:16
And that comes out to be 49 newtons.
01:20
And the maximum value of tension that we can observe is 39 .2.
01:25
So in this case, we see that the object will not accelerate as it is released from rest...