In Ga As, me* = 0.067 me , mh* = 0.53 me , dielectric constant 13.2 , Bohr radius : 0.565 nm Calculate the Bohr exciton radius for the exciton
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Step 1
Step 1: Recall the formula for the reduced mass (Āµ) of the exciton: Āµ = (me* * mh*) / (me* + mh*) where me* is the effective mass of the electron, and mh* is the effective mass of the hole. Show moreā¦
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