00:01
So you have a guinea pig, you have two different traits.
00:06
One is called roughness, smoothness, and then the other is color.
00:10
Rough is dominant to smooth and black dominant to white.
00:15
So you have two parent, female with smooth white and crossed with male with hatter leggers for both.
00:23
First of all, what is the genotype of the two guinea pig when it comes to the smoothness and color? the female has a phenotype of smooth and white.
00:39
So we know that both phenotypes are recessive when it comes to the trait.
00:44
So only when you have homo zeigers recessive, you will have recessive phenotype.
00:49
So this tells us that it must have homo zeigers lower r and homo zeigers lower b.
00:55
So this is a double recessive and homo zeigers.
00:58
And the male is hatter leggers for both traits.
01:01
Since hatter leggers show dominant, it will be a rough and black.
01:11
And hatter leggers means it's capital r, lower r, capital b and lower b.
01:17
The next step, the question asks you to draw a punnett square below, show all the possible combination of allele for the offspring for this cross.
01:24
So let's look at the female.
01:26
Female only has as a homo zeigers lower r and lower b.
01:31
So this means that it only produces one type of gametes, which is lower r and lower b.
01:37
So this means that it will produce four gametes.
01:41
They're all having the same genotype, lower r and lower b.
01:45
Now the male has hatter leggers genotype.
01:49
So it's a lot more complicated.
01:51
We assume r and b are assorted independently.
01:55
So you have different combinations.
01:58
For example, capital r was capital b, capital r assorted with lower b, lower r assorted with capital b or lower r with lower b.
02:14
So you can see that the male produced four possible gametes and the female only produced one type of gametes...