Question

1. In how many ways can 7 cars be parked if there are 10 available parking spaces? Given: n = 10 r= From: $P(n,r) = \frac{n!}{(n-r)!}$ ; then, $P(10, \_) = \frac{10!}{(10- \_)!}$ $P(10, \_) = \_\_\_\_$ 2. In how many ways can 6 people arrange themselves in a row for picture

          1. In how many ways can 7 cars be parked if there are 10 available parking
spaces?
Given: n = 10
r=
From: $P(n,r) = \frac{n!}{(n-r)!}$ ; then,
$P(10, \_) = \frac{10!}{(10- \_)!}$
$P(10, \_) = \_\_\_\_$
2. In how many ways can 6 people arrange themselves in a row for picture

1. In how many ways can 7 cars be parked if there are 10 available parking
spaces?
Given: n = 10
r=
From: P(n,r) = (n!)/((n-r)!) ; then,
P(10, = (10!)/((10- !)
P(10, =
2. In how many ways can 6 people arrange themselves in a row for picture

Added by Tyler O.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Robin Corrigan

Step 1

This can be calculated using the formula for permutations: P(10,7) = 10! / (10-7)! = 10! / 3! Show more…

Show all steps

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In how many ways can 7 cars be parked if there are 10 available parking spaces? Given: n = 10. From: P(n,r) = n! / (n-r)! Then, P(10,7) = 10! / (10-7)! = 10! / 3! A = 6 people arrange themselves in a row for a picture.