In how many ways can a committee of four be chosen from 8 men and 9 women, if the committee must include at least one member of each sex?
Added by Jonathan V.
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The number of ways to choose a committee of four men from 8 men is: $$\binom{8}{4} = \frac{8!}{4!(8-4)!} = \frac{8!}{4!4!} = 70$$ Show more…
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