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Question 3 (5 points): Q3) Write a Java class \texttt{Point} to represent a point with x and y coordinates. The class \texttt{Point} has the following: Attributes: \begin{itemize} \item \texttt{double x} \item \texttt{double y} \end{itemize} Methods: \begin{itemize} \item Setters and getters for x and y. \item \texttt{distance(Point p): double}. This method returns the distance between the two points: p and the calling object. hint: to compute distance between two points, use the equation: $\text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$ \end{itemize} Write another class \texttt{TestPoint} that does the following: 1. Declare two \texttt{Point} objects p1 and p2 2. Read the values of x and y for both points. 3. Compute the distance between the two points using the method \texttt{distance}, if the distance is less than or equal to 5.0 you should print the distance and exit. Otherwise keep reading two more points and printing the distance until you get two points with distance less than or equal to 5.0. Sample run 1: Enter x and y for p1 1 2 Enter x and y for p2 6 8 Distance is 7.810249675906654 which is \textgreater 5. Try again. Enter x and y for p1 2 6 Enter x and y for p2 9 18 Distance is 13.892443989449804 which is \textgreater 5. Try again. Enter x and y for p1 1 1 Enter x and y for p2 4 3 The two points are close. The distance between them is 3.605551275463989 which is less than 5 Sample run2: Enter x and y for p1 0 0 Enter x and y for p2 0 0 The two points are close. The distance between them is 0.0 which is less than or equal to 5 Sample run3: Enter x and y for p1 18 5 Enter x and y for p2 15 5 The two points are close. The distance between them is 5.0 which is less than or equal to 5

          Question 3 (5 points):
Q3) Write a Java class \texttt{Point} to represent a point with x and y coordinates. The
class \texttt{Point} has the following:
Attributes:
\begin{itemize}
\item \texttt{double x}
\item \texttt{double y}
\end{itemize}
Methods:
\begin{itemize}
\item Setters and getters for x and y.
\item \texttt{distance(Point p): double}. This method returns the distance between the two
points: p and the calling object.
hint: to compute distance between two points, use the equation:
$\text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$
\end{itemize}
Write another class \texttt{TestPoint} that does the following:
1. Declare two \texttt{Point} objects p1 and p2
2. Read the values of x and y for both points.
3. Compute the distance between the two points using the method \texttt{distance}, 
if the distance is less than or equal to 5.0 you should print the distance and
exit. Otherwise keep reading two more points and printing the distance
until you get two points with distance less than or equal to 5.0.
Sample run 1:
Enter x and y for p1 1 2
Enter x and y for p2 6 8
Distance is 7.810249675906654 which is \textgreater 5. Try again.
Enter x and y for p1 2 6
Enter x and y for p2 9 18
Distance is 13.892443989449804 which is \textgreater 5. Try again.
Enter x and y for p1 1 1
Enter x and y for p2 4 3
The two points are close.
The distance between them is 3.605551275463989 which is
less than 5
Sample run2:
Enter x and y for p1 0 0
Enter x and y for p2 0 0
The two points are close.
The distance between them is 0.0 which is less than or
equal to 5
Sample run3:
Enter x and y for p1 18 5
Enter x and y for p2 15 5
The two points are close.
The distance between them is 5.0 which is less than or
equal to 5

Question 3 (5 points):
Q3) Write a Java class Point to represent a point with x and y coordinates. The
class Point has the following:
Attributes:

* double x

* double y

Methods:

* Setters and getters for x and y.

* distance(Point p): double. This method returns the distance between the two
points: p and the calling object.
hint: to compute distance between two points, use the equation:
Distance = √((x2 - x1)^2 + (y2 - y1)^2)

Write another class TestPoint that does the following:
1. Declare two Point objects p1 and p2
2. Read the values of x and y for both points.
3. Compute the distance between the two points using the method distance,
if the distance is less than or equal to 5.0 you should print the distance and
exit. Otherwise keep reading two more points and printing the distance
until you get two points with distance less than or equal to 5.0.
Sample run 1:
Enter x and y for p1 1 2
Enter x and y for p2 6 8
Distance is 7.810249675906654 which is 5. Try again.
Enter x and y for p1 2 6
Enter x and y for p2 9 18
Distance is 13.892443989449804 which is 5. Try again.
Enter x and y for p1 1 1
Enter x and y for p2 4 3
The two points are close.
The distance between them is 3.605551275463989 which is
less than 5
Sample run2:
Enter x and y for p1 0 0
Enter x and y for p2 0 0
The two points are close.
The distance between them is 0.0 which is less than or
equal to 5
Sample run3:
Enter x and y for p1 18 5
Enter x and y for p2 15 5
The two points are close.
The distance between them is 5.0 which is less than or
equal to 5

Added by Cheryl B.

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