Question

slt $t1, $t0, $t2 beq $t0, $0, loc1 addi $t0, $t0, 1 loc1: addi $t0, $t0, 1 Register Initial Final Memory Initial Final value Value value Value $t0 0x00000005 ? 0x00070004 0x19B09BE1 ? $t1 0xF0001023 ? 0x00070000 0x789119ED ? $t2 0x00070000 ? 0x0006FFFC 0x5555AAAA ?

          slt $t1, $t0, $t2
beq $t0, $0, loc1
addi $t0, $t0, 1
loc1: addi $t0, $t0, 1
Register Initial Final Memory Initial Final
value Value value Value
$t0 0x00000005 ? 0x00070004 0x19B09BE1 ?
$t1 0xF0001023 ? 0x00070000 0x789119ED ?
$t2 0x00070000 ? 0x0006FFFC 0x5555AAAA ?

slt t1,t0, t2
beqt0, 0, loc1
addit0, t0, 1
loc1: addit0, t0, 1
Register Initial Final Memory Initial Final
value Value value Valuet0 0x00000005 ? 0x00070004 0x19B09BE1 ?
t1 0xF0001023 ? 0x00070000 0x789119ED ?t2 0x00070000 ? 0x0006FFFC 0x5555AAAA ?

Added by Cody M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Kratika Bhadauria

Step 1

slt $t1, $t0, $t2 This instruction sets $t1 to 1 if $t0 is less than $t2, and 0 otherwise. Since $t0 is 0x00000005 and $t2 is 0x00070000, $t0 is not less than $t2. Therefore, $t1 will be set to 0. Show more…

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In MIPS32 assembly language, what are the final values? slt $t1, $t0, $t2 beq $t0, $0, loc1 addi $t0, $t0, 1 loc1: addi $t0, $t0, 1 Register Initial value Final Value Memory Initial value Final Value $t0 0x00000005 ? 0x00070004 0x19B09BE1 ? $t1 0xF0001023 ? 0x00070000 0789119ED $t2 0x00070000 0x0006FFFC 0x5555AAAA ?