00:01
So in this question we had given here, out of 44 students, out of 44 students present, present, 22 study chinese, 22 study chinese and 14 study french.
00:25
12 students study neither language.
00:27
12 students study neither language.
00:36
So the solution to this question is, solution is number of students who knows language is equal to number of students who knows who knows language is equal to language is equal to 44.
01:04
Minus 12 is equal to 32 so chinese is c and french is f f so here n c union f is equal to 32 now n c c union f is equal to n c plus n f minus n c intersection f so this will become as 32 equal to 22 plus 14 minus nc intersection f.
01:51
So n c intersection f is equal to 4.
01:57
Now four students knows both chinese and french.
02:03
4 students students knows both chinese and french.
02:17
Now first is only chinese, only chinese, 22 minus 4 that is equal to 18.
02:30
Only french is equal to, only french is equal to 14 minus 4 is equal to 10.
02:39
Third one is both chinese and french, both chinese and french...