00:01
In this question, customers at a bank are rated with a1 to a3 rating, a1 being the lowest risk and a3 being the highest risk.
00:11
There are 30 % customers with lowest risk, a1, 60 % with a2 rating and 10 % with a3 rating.
00:19
And the defaulters with a1 rating are 1%.
00:23
With a2 rating are 10%, and with a3 rating are 18%.
00:29
Now, before we answer all this, let's define the event.
00:38
So i'm going to let a1 event be the event of person with a1 risk rating.
00:47
A2 be a person with a2 risk rating, a3 person with a3 risk rating, and d be the event of a defaulter.
00:55
So let's write out all the probabilities we are given.
01:00
So we have pa1 is 30%.
01:04
So that is 0 .3.
01:06
P -a -2 is 60%, so that's 0 .6.
01:12
Probability of a3, that's 10%, so that's 0 .1.
01:17
Now, we are also given that probability of defaulters to d given a1 rating is 0 .01, because 1%.
01:34
So, conditional probability means d intersect a1 over probability of a1 will be equals to 0 .01 so this means now p a1 is 0 .3 over here so this means it's 0 .01 this p a1 i move up okay times 0 .3 i'm going to get 0 .003 now similarly we can find the we are given probability of the default given a2 rating is 10 % over here so that is 0 .1 so again conditional probability okay now p a2 is 0 .6 so i'm going to bring this up which is 0 .6 times with my 0 .1 i will get 0 .06 now similarly you can find your pd intersect a 3 and that will be taking 18 % of 0 .18 times your p, a3, which is 0 .1, and you will get 0 .018.
03:05
Now, what does this mean all? now, in a 3, you have a1, a2, a3, right? so the probability of a1 is 0 .3, a2 is 0 .6, and a1 is 0 .1.
03:22
Now, you'll split into defaulters and non -defaulter.
03:28
Now, d prime means the complement of these.
03:30
So these are people who don't default.
03:36
Now, you can see that i wouldn't have this part yet, okay, but you can see that d intersect a1 means the probability of d and a1 will be 0 .03, so i'm just going to put the 0 .03 here.
03:54
And d intersect a2 is 0 .06.
03:57
So i'm going to put 0 .06 here.
03:59
And d intersect a3 is the same as a3 in a set d, so this is 0 .018.
04:07
Okay, let's answer the question in a...