00:01
Hi, here in this given problem, power of the coffee maker that is given as p is equal to 1200 watt.
00:19
Current passing through it that is 10 ampere and it is obvious that the voltage applied for it, it will be 120 volt.
00:31
We can verify it using the relation p is equal to v i.
00:35
Now, with this data we can find resistance of coffee maker using an expression for the power p is equal to i square r.
00:52
So r will be given by p by i square means this r is equal to 1 ,200 watt divided by square of 10 ampere.
01:05
So it comes out to be equal to 12 o 'ong.
01:07
And on changing the voltage or current, resistance of the coffee maker will remain constant.
01:14
There will be no change in it.
01:18
Now the current is, now the voltage is reduced by 10%.
01:27
So when v -dash is 10 % lower, means 10 % lower from this 120 -volt, it comes to.
01:40
Out to be equal to 1008 volt...