00:01
So for question number two, you are given the sample mean to be equal to 49 .5.
00:10
Population standard deviation to be 3 .6.
00:13
Our sample size is given us 120.
00:17
So our now hypothesis will be muon is equal to 48 .8.
00:21
And the alternative is noon is not equal to 48 .8.
00:27
So now this corresponds to a two -tailed test.
00:31
So now we are giving our.
00:33
To be 0 .05 so our z critical will be equal to 1 .96 using the alpha so this will actually set alpha on 2 and make you a 6 so we need to find our test statistic so our z will be equal to x bar minus me over sigma and the root of n and this is equal to 49 .5 minus 48 .8 over 3 .6 over the root of 120.
01:10
So we get z to equal 2 .13.
01:16
So now comparing our test statistic and our critical value.
01:21
You can see that 2 .13 is greater than the critical value of 1 .96.
01:28
So we are going to reject our no hypothesis.
01:38
Also we can find for the p -val 3 is greater than the critical value of 1 .96.
01:40
So we are going to reject our no hypothesis...