In Problems 29 and 30, use the probabilities in the first tree diagram to find the probability of each branch of the second tree diagram. 29. Start Start $\frac{1}{4}$ $\frac{3}{4}$ $\frac{1}{5}$ $\frac{4}{5}$ $\frac{3}{5}$ $\frac{2}{5}$ B A A' B' B B' A B A' A B' A'
Added by Anthony A.
Close
Step 1
Step 1: The probability of the branch "Start - B - A" is the product of the probabilities of each individual event: $\frac{1}{4} \times \frac{1}{5} = \frac{1}{20}$. Show more…
Show all steps
Your feedback will help us improve your experience
David Nguyen and 93 other Intro Stats / AP Statistics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Rework problem 1 from section 3.4 of your text, involving probabilities on a tree diagram. Construct a copy of figure 3.15 in your text, where the first outcome is one of A and B. The second outcome in each case is one of a and b. Use the following probabilities instead of those given in your text: Pr[A] = 7/9 Pr[B] = 2/9 Pr[a|A] = 2/7 Pr[b|A] = 5/7 Pr[a|B] = 2/3 Pr[b|B] = 1/3 Find the following missing probabilities: (1) Pr[B] = (2) Pr[b] = 1071/1701 (3) Pr[b|B] = (4) Pr[B|b] =
David N.
A tree diagram has two stages. Stage 1 has two nodes and stage 2 has four nodes. In stage 1, the branch from the starting position to node A is labeled 0.4. The branch from the starting position to node B is an answer blank. In stage 2, the branch from node A to node C is an answer blank. The branch from node A to node D is labeled 0.5. In stage 2, the branch from node B to node C is labeled 0.1. The branch from node B to node D is an answer blank. Supply the missing quantities: Outcome P(A ∩ C) = P(A ∩ D) = P(B ∩ C) = P(B ∩ D) =
Lauren S.
Rework problem 17 from section 3.3 of your text, involving filling in missing probabilities on a tree diagram. Construct a copy of figure 3.10 in your text, where the first outcome is one of (A, B, C) and the second outcome in each case is one of (1, 2). Use the following probabilities instead of those given in your text: Pr[A] = 1/16 Pr[A1] = 1/24 Pr[A2] = 1/8 Pr[1|B] = 1/2 Pr[2|B] = 1/2 Pr[B1] = 1/4 Pr[B2] = 1/4 Pr[C1] = 1/4 Pr[C2] = 1/12 Find the following missing probabilities: (1) Pr[1|A] = (2) Pr[B] = (3) Pr[C] = (4) Pr[2|C] =
Ariana N.
Recommended Textbooks
Elementary Statistics a Step by Step Approach
The Practice of Statistics for AP
Introductory Statistics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD