00:01
Okay, so we just need to use kepler's third law to find the period of the planet that is circling the star.
00:10
The star is 0 .0058 au away from the planet, and the mass of the star we know is 0 .13 times the mass of the sun.
00:27
And they give us the mass of the sun, a gravitational constant of 6 .6 .6.
00:32
7 times 10 to the negative 11, and then just the conversion of au to meters.
00:39
So 1au is 1 .50 times 10 to the 11 meters.
00:43
And so then we have kepler's law over here.
00:45
That's p squared equals 4 pi squared times the distance cubed over g times mass of the star.
00:55
So we'll go ahead and use that.
00:58
Just take the square root of both sides.
01:10
And we have everything we need so we can just go ahead and plug everything in.
01:14
And so i'm just going to pull out two pi from the inside.
01:23
All right, so we have that, we do want to put this into meters.
01:28
So what we'll do is say 0 .0058.
01:36
A .u...