Question

In right-angled triangle ( A B C, A B=10 sqrt{3} mathrm{~cm}, B C=20 ) cm and ( angle A=90^{circ} ). An equilateral triangle ( A B D ) is constructed with base ( A B ) and vertex ( D ), at a maximum possible distance from ( C ). Find the length of ( C D ). (A) ( 10 sqrt{7} mathrm{~cm} ) (B) ( 10 sqrt{11} mathrm{~cm} ) (C) ( 10 sqrt{12} mathrm{~cm} ) (D) ( 10 sqrt{14} mathrm{~cm} )

          In right-angled triangle ( A B C, A B=10 sqrt{3} mathrm{~cm}, B C=20 ) cm and ( angle A=90^{circ} ). An equilateral triangle ( A B D ) is constructed with base ( A B ) and vertex ( D ), at a maximum possible distance from ( C ). Find the length of ( C D ).
(A) ( 10 sqrt{7} mathrm{~cm} )
(B) ( 10 sqrt{11} mathrm{~cm} )
(C) ( 10 sqrt{12} mathrm{~cm} )
(D) ( 10 sqrt{14} mathrm{~cm} )

In right-angled triangle ( A B C, A B=10 sqrt3 mathrm cm, B C=20 ) cm and ( angle A=90^circ ). An equilateral triangle ( A B D ) is constructed with base ( A B ) and vertex ( D ), at a maximum possible distance from ( C ). Find the length of ( C D ).
(A) ( 10 sqrt7 mathrm cm )
(B) ( 10 sqrt11 mathrm cm )
(C) ( 10 sqrt12 mathrm cm )
(D) ( 10 sqrt14 mathrm cm )

Added by Ujjwal S.

43 Years JEE ADVANCED (1978-2020) + JEE MAIN Chapterwise & Topicwise Solved Papers Physics

Disha Experts 16th Edition

Chapter 10

Instant Answer

Solved by Expert Donna Densmore

10/19/2024

Step 1

In right-angled triangle \(ABC\), \(AB = 10\sqrt{3}\) cm, \(BC = 20\) cm, and \(\angle A = 90^\circ\). An equilateral triangle \(ABD\) is constructed with base \(AB\). Show more…

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