Question

In springboard diving, the diver strides out to the end of the board, takes a jump onto its end, and uses the resultant spring-like nature of the board to help propel him into the air. Assume that the diver's motion is essentially vertical. He leaves the board, which is 3.2 m above the water, with a speed of 6 m/s. (a) How long is the diver in the air, from the moment he leaves the board until he reaches the water? (b) What is the speed of the diver when he reaches the water?

          In springboard diving, the diver strides out to the end of the board, takes a jump onto its end, and uses the resultant spring-like nature of the board to help propel him into the air. Assume that the diver's motion is essentially vertical. He leaves the board, which is 3.2 m above the water, with a speed of 6 m/s.
(a) How long is the diver in the air, from the moment he leaves the board until he reaches the water? 
(b) What is the speed of the diver when he reaches the water?
        
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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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In springboard diving, the diver strides out to the end of the board, takes a jump onto its end, and uses the resultant spring-like nature of the board to help propel him into the air. Assume that the diver's motion is essentially vertical. He leaves the board, which is 3.2 m above the water, with a speed of 6 m/s. (a) How long is the diver in the air, from the moment he leaves the board until he reaches the water? (b) What is the speed of the diver when he reaches the water?
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Transcript

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00:01 In this problem in part a we have to find how long is the diver in the air from the movement he leaves the boat until he reaches the water so this is the driver and initial speed is 6 meter per second in the vertical direction in the upper word so the time we will take suppose p now we will use a kinematic equation s is equal to ut plus half 80 square.
00:36 So the vertical displacement will be 3 .2 in the downward direction.
00:41 So i will take negative sign minus 3 .2.
00:46 When he reaches here, the vertical displacement will be minus 3 .2.
00:52 And the vertical speed initial is 6 into t plus half.
00:57 Excellation is minus 9 .8 into p square.
01:02 So now we can write this 4 .9 t square minus 60 minus 3 .2 is equal to 0.
01:14 Now this is the quadratic equation which we need to solve.
01:19 So the value of time after solving this we will get this is 1 .63 seconds...
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