00:01
In this problem, we have been given a graph of y is equal to f of x, and we need to find the slope of the second line through the points minus 3, f of minus 3, and 2, f of 2.
00:18
So if we have a look at the graph, then we can see that the graph passes through the point minus 3, minus 3.
00:26
So that will mean that the point minus 3 comma f of minus 3 is the point minus 3 comma minus 3.
00:34
Also, we can see that the graph of the function passes through the point 2 comma minus 1.
00:40
So the point 2 f of 2 is 2 comma minus 1.
00:44
So we need to find the slope of the second line through these points.
00:47
So that means we just need to find the slope of the line through these two points.
00:52
So if we consider this first point to be the point x1y1, and the second point to be x2 y2.
01:00
Then the formula for the slope of a line through the points x1, y1, and x2, y2, is known to m is equal to y2 minus y1 by x2 minus x1...