Question

In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is approximately $2.20 \times 10^{6} \mathrm{~m} / \mathrm{s}$. Find (a) the force acting on the electron as it revolves in a circular orbit of radius $0.529 \times$ $10^{-10} \mathrm{~m}$ and (b) the centripetal acceleration of the electron.

Name: In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is approximately 2.20 × 10^6 m / s. Find (a) the force acting on the electron as it revolves in a circular orbit of radius 0.529 × 10^-10 m and (b) the centripetal acceleration of the electron.
Uploaded: 2022-07-12T01:55:29-08:00
Duration: 1 min 41 s
Channel: Madhur L
Description: In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is approximately 2.20 × 10^6 m / s. Find (a) the force acting on the electron as it revolves in a circular orbit of radius 0.529 × 10^-10 m and (b) the centripetal acceleration of the electron.

          In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is approximately $2.20 \times 10^{6} \mathrm{~m} / \mathrm{s}$. Find (a) the force acting on the electron as it revolves in a circular orbit of radius $0.529 \times$ $10^{-10} \mathrm{~m}$ and (b) the centripetal acceleration of the electron.

Added by Cassidy B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Madhur L

07/12/2022

Step 1

20 \times 10^6 \, \text{m/s}\) Radius of circular path, $r = 0.529 \times 10^{-10} \, \text{m}$ The centripetal force acting on the electron is given by: \[ F_c = \frac{m \cdot v^2}{r} \] ** Show more…

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In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is approximately $2.20 \times 10^{6} \mathrm{~m} / \mathrm{s}$. Find (a) the force acting on the electron as it revolves in a circular orbit of radius $0.529 \times$ $10^{-10} \mathrm{~m}$ and (b) the centripetal acceleration of the electron.