00:01
Hello students, let's solve this question.
00:02
Here, we can apply the kirchhoff's current law at the node a.
00:10
So, it will be va -vc divided by 6 plus va -17 divided by 2 plus va divided by 3 is equal to 0.
00:27
That can be written as va -vc plus 3 into va minus 51 plus 2 into va is equal to 0 or we can write 6 va -vc is equal to 51.
00:43
Let's mark this as equation number 1.
00:45
Now, applying the kirchhoff's current law at the node b, we can write 17 -va divided by 2 plus 17 -vc divided by 4 is equal to 0.
01:05
That is 34 minus 2 into va plus 17 minus vc is equal to 0.
01:14
On solving, we will get the equation as 2 va plus vc is equal to 51.
01:20
Mark this as equation number 2.
01:22
Similarly, applying the kirchhoff's current law at node c, we can write vc divided by 12 plus vc minus 17 divided by 4 plus vc minus va divided by 6 is equal to 0.
01:38
Solving, we will get the equation as 6 vc minus 2 into va is equal to 51.
01:44
Mark this equation number 3.
01:46
Now, multiplying equation 1 with 6, we will get va value which is equal to 10 .5 volt...