In the circuit below $C_1 = C_3 = 3 \mu F$, and $C_2 = 6 \mu F$, the battery supplies 9 V. (d) What is the potential energy stored by capacitor 3?
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Capacitors $C_1$ and $C_2$ are in series, so their equivalent capacitance $C_{12}$ is given by: $\frac{1}{C_{12}} = \frac{1}{C_1} + \frac{1}{C_2} = \frac{1}{3} + \frac{1}{6} = \frac{3}{6} = \frac{1}{2}$ $C_{12} = 2 \, \mu F$ Show more…
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