Question

II. In the circuit below, the input voltage is Vin=Vin peak cos(?t), R=10 K? and C=5nF ?vin R C ?vout a) Show that the output voltage is Vout=VLO cos (?t-?), where VLO=Vin peak/?1 + (?RC)^2 b) Show that this result justifies calling this circuit a low-pass filter c) Find an expression for the phase constant ? in terms of R,C and ? d) At what frequency is VLO=(1/?2) Vin peak? That particular frequency is known as the 3dB frequency, or f3dB, of the circuit

          II. In the circuit below, the input voltage is Vin=Vin peak cos(?t), R=10 K? and C=5nF
?vin R C ?vout
a) Show that the output voltage is Vout=VLO cos (?t-?), where VLO=Vin peak/?1 + (?RC)^2
b) Show that this result justifies calling this circuit a low-pass filter
c) Find an expression for the phase constant ? in terms of R,C and ?
d) At what frequency is VLO=(1/?2) Vin peak? That particular frequency is known as the 3dB frequency, or f3dB, of the circuit

II. In the circuit below, the input voltage is Vin=Vin peak cos(?t), R=10 K? and C=5nF
?vin R C ?vout
a) Show that the output voltage is Vout=VLO cos (?t-?), where VLO=Vin peak/?1 + (?RC)^2
b) Show that this result justifies calling this circuit a low-pass filter
c) Find an expression for the phase constant ? in terms of R,C and ?
d) At what frequency is VLO=(1/?2) Vin peak? That particular frequency is known as the 3dB frequency, or f3dB, of the circuit

Added by Felicia J.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

07/06/2022

Step 1

Step 1: Calculate the impedance of the circuit. Show more…

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In the circuit below, the input voltage Vin = Vin peak * cos(wt), R = 10 kΩ, and C = 5 nF. Show that the output voltage Vout = VLO cos(wt - δ), where VLO = Vin peak / sqrt(1 + (wRC)^2). Show that this result justifies calling this circuit a low-pass filter. Find an expression for the phase constant δ in terms of R, C, and w. At what frequency is VLO = (1/sqrt(2)) * Vin peak? That particular frequency is known as the 3dB frequency, or f3dB, of the circuit.