00:01
Hi, so hearing this question using mesh analysis we have to find out i not.
00:06
Here we have given r is 2 o.
00:11
Now from this circuit diagram we will get i1, i2, i3 and i 4 are mesh currents from which i 1 and i 2 are super mesh currents and therefore we will get i2 minus i1 will be equal to 10.
00:59
We will call this as equation number 1.
01:02
Now applying krechhoff's voltage law for i1 and i2.
01:13
We will get 4 plus 2 i 1 plus 8 plus 1 plus 2 i 2 i 2 minus 8 plus 1 plus 1 plus 2 i 2 minus 2 2 i3 minus 2 i 4 will be equal to 60.
01:39
Therefore we will get 6 i1 plus 11 i2 minus 2 i 3 minus 2 i 4 will be equal to 60.
01:55
We will call this as equation number 2.
01:57
Similarly applying krechhoff's voltage law at i 3.
02:02
At i3 there is direct current source, so we will get i3 will be equal to minus 5.
02:10
Call this as equation number 3.
02:13
And applying kreechof's voltage law at i4, we will get 2 plus 1 plus 4 i4 minus 2i2 minus i3 will be equal to minus 22 .5.
02:38
Therefore, we will get 7i4 minus 2 i2 minus i3 will be equal to minus 22 .5...